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4 years ago

Ohms's law of electricity states that V=IR, where V is voltage, I the current, and R represents the resistance.

Mathematics

1 answer:

AysviL [449]4 years ago

6 0

Answer:

$i = \frac{v}{r}$

2)no ohms

$r = \frac{v}{i}$

$\frac{550}{1.5} = r \\ \\ r = 366.66$

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Which graph represents the function -2x - 5y = -10? <br> Please explain!!

damaskus [11]

The answer would be J because if the equation was transferred into a positive then it would be 2y and 5x marking 5x on the bottom and 2y vertically.
Hope this helps!!

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3 years ago

Read 2 more answers

A factory begins the day with 6,000 packaged light bulbs. the machines in the factory can package 1,200 light bulbs every hour f

Alex_Xolod [135]

Answer:

If the factory starts with 6,000 packaged light bulbs at the beginning of the day, and the factory produces 1,200 light bulbs every hour for the next 5 hours then in 5 hours there will be 6,000 light bulbs.

6,000 + (1,200 x 5) = ?
6,000 + 6,000 = ?
? = 12,000 lightbulbs

Step-by-step explanation:

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#TheWizzer

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2 years ago

The exponent equivalent of 20 x 20 x 20 is

geniusboy [140]

Answer:

20 to the 5th power

Step-by-step explanation:

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3 years ago

The cost of one can of soda if 6 cans cost n

Arturiano [62]

Answer

if 6 cans cost n

1 can would cost n/6

Example

6 cans cost 12

1 can would cost 12/6

which is 2

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3 years ago

Mrs. Carlyle bought a bag of nuts for her children. Phillip, Joy, Brent, and Preston took some from the bag.Phillip took 1/3. Jo

BARSIC [14]

Answer:

Originally there was 324 nuts in the bag.

Phillip took 108, Joy took 54, Brent took 81 and Preston took 10.

Step-by-step explanation:

Let's call the total amount of nuts N, and the number of nuts each child took by the initial of their name (Phillip will be P1 and Preston will be P2).

So we can write the following equations:

P1 = N/3

After removing N/3, the remaining nuts is (N - N/3):

J = (N - N/3)/4 = (2N/3)/4 = N/6

After removing N/6 from (N - N/3), the remaining nuts is (N - N/3 - N/6):

B = (N - N/3 - N/6)/2 = (N/2)/2 = N/4

P2 = 10

In the final there were 71 nuts remaining, so we have that:

N - N/3 - N/6 - N/4 - 10 = 71

N - N/3 - N/6 - N/4 = 81

N/4 = 81

N = 324 nuts

The amount of nuts took by each child is:

P1 = N/3 = 108 nuts

J = N/6 = 54 nuts

B = N/4 = 81 nuts

P2 = 10 nuts

8 0

4 years ago