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vodka [1.7K]
3 years ago
12

For the cyclic quadrilateral ABCD, which statement is true? A) The sum measure of ∠A and ∠B equals 180°. B) The sum measure of ∠

A and ∠D equals 180°. C) The sum measure of ∠B and ∠D equals 180°. D) The sum measure of ∠C and ∠D equals 180°.

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
7 0

Answer:

C

Step-by-step explanation:

kifflom [539]3 years ago
6 0
See the picture attached to better understand the problem

we know that
A quadrilateral is called Cyclic quadrilateral <span>if its all vertices lie on the circle.
</span><span>The opposite angles of a Cyclic - quadrilateral are supplementary
</span>so
∠A+∠C=180°
and
∠B+∠D=180°

therefore
the answer is
<span>C) The sum measure of ∠B and ∠D equals 180°</span>

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Jet001 [13]
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3 years ago
Given that P(E) = 0.38, P(F) = 0.38, and P(E ∩ F) = 0.12. Find P(E ∪ F, how do I work this out?
natulia [17]

Answer: The value of P(E∪F) = 0.64.

Step-by-step explanation:

Since we have given that

P(E) = 0.38

P(F) = 0.38

P(E∩F) = 0.12

So, we need to find the P(E∪F).

As we know the formula for the sets.

P(E\cup F)=P(E)+P(F)-P(E\cap F)\\\\P(E\cup F)=0.38+0.38-0.12=0.64\\\\P(E\cup F)=0.64

Hence,the value of P(E∪F) = 0.64.

3 0
3 years ago
Please help on this
Whitepunk [10]

Answer:

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Step-by-step explanation:

Hope that helps

4 0
3 years ago
At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c
Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

np=200*0.164=32.8 \geq 10

n(1-p)=200*(1-0.164)=167.2 \geq 10

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

The mean is given by:

p =0.164

And the deviation is given by:

\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=200, p=0.164)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=200*0.164=32.8 \geq 10

n(1-p)=200*(1-0.164)=167.2 \geq 10

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

The mean is given by:

p =0.164

And the deviation is given by:

\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0
3 years ago
Triangle ABC is reflected over the Y axis. what are the coordinates of the reflected triangle
Liula [17]
Original Coordinates: A(1, 3) B(4, 5) C(3, 1)

Now, It is reflected over y-axis, so the sign of their x-coordinate will change.,

It would be: A'(-1, 3) B'(-4, 5) C'(-3, 1)

Hope this helps!
8 0
3 years ago
Read 2 more answers
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