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tatyana61 [14]
3 years ago
13

Which answer explains one way that the length of this line segment can be determined?

Mathematics
2 answers:
masha68 [24]3 years ago
8 0
4-1=3 distance, length of line equals 3.
jarptica [38.1K]3 years ago
7 0
Subtract 4 and 1
4-1=3
distance or length of this line segment is 3
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You are choosing between two health clubs. Club A offers membership for a fee of $12 plus a monthly fee of $28. Club B offers me
EleoNora [17]

A has fixed one time fee of $12 and if you go to it say "m" months you pay $28 for each month, so your total cost at A is really 12 + 28m.

B has a fixed one time fee of $20 and if you go to it "m" months you pay $26 for each month, so you total cost at B is 20 + 26m.

how many months for the cost to be the same?

\stackrel{A}{12+28m}=\stackrel{B}{20+26m}\implies 12+2m=20\implies 2m=8\implies m=\cfrac{8}{2}\implies m=4

well, since the cost for both is the same, we can just get A's, knowing that B is the same

12+28(4)\implies 12+112\implies 124

5 0
3 years ago
Which of these values could be the slope of the line? Select two options. –2 0 3
Valentin [98]

Answer:

-2 and 3

Step-by-step explanation:

These two are slopes. All three are technically slopes but a slope of 0 is just a horizontal line.

8 0
3 years ago
Read 2 more answers
Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1
svet-max [94.6K]

Answer:

a) 0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

b) 0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.0 ounces and a standard deviation of 1.1 ounces.

This means that \mu = 8, \sigma = 1.1

(a) If 5 potatoes are randomly selected, find the probability that the mean weight is less than 9.3 ounces?

n = 5 means that s = \frac{1.1}{\sqrt{5}} = 0.4919

This probability is the pvalue of Z when X = 9.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{9.3 - 8}{0.4919}

Z = 2.64

Z = 2.64 has a pvalue of 0.9959

0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

(b) If 6 potatoes are randomly selected, find the probability that the mean weight is more than 9.0 ounces?

n = 6 means that s = \frac{1.1}{\sqrt{6}} = 0.4491

This probability is 1 subtracted by the pvalue of Z when X = 9. So

Z = \frac{X - \mu}{s}

Z = \frac{9 - 8}{0.4491}

Z = 2.23

Z = 2.23 has a pvalue of 0.9871

1 - 0.9871 = 0.0129

0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

8 0
3 years ago
Jeff saw 7 identical
Shkiper50 [21]

Answer:

$45

Step-by-step explanation:

5 0
3 years ago
1/3x+4=x-2<br><br><br> SHOW WORK
Len [333]
X= -3
I hope that helps :)

8 0
3 years ago
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