Question

Triangle ABC is an isosceles triangle in which side AB = AC. What is the perimeter of triangle ABC? 5 + StartRoot 10 EndRoot units 10 + StartRoot 10 EndRoot units 10 StartRoot 10 EndRoot units 50 units

Answer 1

Answer:

b

Step-by-step explanation:

Answer 2

Answer:

Option (2)

Step-by-step explanation:

This question is incomplete; find the picture attached which makes this question complete.

Vertices of the given triangle are A(-2, -4), B(2, -1) and C(3, -4).

Length of AB = $\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

AB = $\sqrt{(2+2)^2+(-1+4)^2}$

     = $\sqrt{16+9}$

     = 5 units

Since AB = AC

AC = 5 units

Similarly, BC = $\sqrt{(3-2)^2+(-4+1)^2}$

BC = $\sqrt{10}$ units

Therefore, perimeter of the given triangle = AB + AC + BC

                                                                      = 5 + 5 + √10

                                                                      = (10 + √10) units

Option (2) will be the answer.