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Sever21 [200]
3 years ago
12

Is (-5,2) a solution to this system of equations? x=-5 y=2x+10

Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0

Answer: No, it's not the solution

Explanation:

Let's plug x = -5 into the second equation

y = 2x+10

y = 2(-5)+10

y = -10+10

y = 0

This shows that (-5,0) is the actual solution, instead of (-5,2)

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Angles around a point equal 360°, so n = 360 - 291 = 69°

Thus, as angles in a triangle add to 180°, m = 180 - 31 - 69 = 80°

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2 years ago
20 points helpp!!! i need it to be ready soon:/
Shkiper50 [21]

Answer:

Q7) 25.5

Q8) 25

Q9) 10

Q10) 12.7

Q11) 34

Q12) 24

Step-by-step explanation:

Q7) c² = a² + b²

x² = 18² + 18²

x = √18² + 18²

x = 18√2 = 25.5

Q8) c² = a² + b²

x² = 20² + 15²

x = √20² + 15²

x = 25

Q9) c² = a² + b²

26² = 24² + x²

x = √26²-24²

x = 10

Q10) c² = a² + b²

x² = 9² + 9²

x = √9² - 9²

x = 9√2 = 12.7

Q11) c² = a² + b²

x² = 30² + 16²

x = √30² + 16²

x = 34

Q12) c² = a² + b²

25² = x² + 7²

x = √25² - 7²

x = 24

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4 0
3 years ago
Burning coal yields about 30 x 106 joules of energy per kilogram of coal burned, but only 30% of that energy goed into electrici
abruzzese [7]

Answer:

Number of bulbs which can be lit using 1 kg of coal = 9

Step-by-step explanation:

Energy yielded by burning 1 kg of coal = 30 × 106 joules

                                                                = 3180 joules

Amount of energy that can be used for electricity = 30 % of 3180 joules

                                                                                   = 0.30 × 3180

                                                                                    = 954 joules

Energy needed for lighting one bulb = Wattage of bulb × No. of hours of lighting

⇒ Energy needed for lighting one bulb = 100 × 1

                                                                  = 100 joules

\text{Now, Number of bulbs which can be lit for one hour = }\frac{954}{100}\\\\\implies\bf\textbf{Number of bulbs = }9.54\approx 9

Hence, Number of bulbs which can be lit using 1 kg of coal = 9

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