Angles around a point equal 360°, so n = 360 - 291 = 69°
Thus, as angles in a triangle add to 180°, m = 180 - 31 - 69 = 80°
Answer:
Q7) 25.5
Q8) 25
Q9) 10
Q10) 12.7
Q11) 34
Q12) 24
Step-by-step explanation:
Q7) c² = a² + b²
x² = 18² + 18²
x = √18² + 18²
x = 18√2 = 25.5
Q8) c² = a² + b²
x² = 20² + 15²
x = √20² + 15²
x = 25
Q9) c² = a² + b²
26² = 24² + x²
x = √26²-24²
x = 10
Q10) c² = a² + b²
x² = 9² + 9²
x = √9² - 9²
x = 9√2 = 12.7
Q11) c² = a² + b²
x² = 30² + 16²
x = √30² + 16²
x = 34
Q12) c² = a² + b²
25² = x² + 7²
x = √25² - 7²
x = 24
!!
Answer:
Number of bulbs which can be lit using 1 kg of coal = 9
Step-by-step explanation:
Energy yielded by burning 1 kg of coal = 30 × 106 joules
= 3180 joules
Amount of energy that can be used for electricity = 30 % of 3180 joules
= 0.30 × 3180
= 954 joules
Energy needed for lighting one bulb = Wattage of bulb × No. of hours of lighting
⇒ Energy needed for lighting one bulb = 100 × 1
= 100 joules

Hence, Number of bulbs which can be lit using 1 kg of coal = 9
You can do 3 quarter's and 9 nickels. or 12 dimes or half dollar and quarter and 9 nickels