(b^7/4^5)^-3 i need help its urgent
1 answer:
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Combine like terms.
Since 7x and 6x both have a variable of x, you can combine them.
After that, you are left with:
You also have two numbers without variables; 11 and 3. You can also combine those.
So, your final answer would be:
Answer:
Step-by-step explanation:
Part A:
We have two equations in the given question:
y=8x and y=2x+2
Then these two equations will intersect at a point where y is same fro both the equations:
In equation y=8x we will exchange y with the other equation which is y=2x+2 then we would have 8x=2x+2..
Part B:
8x = 2x + 2. Take the integer values of x between −3 and 3
x= -3
8(-3)=2(-3)+2
-24=-6+2
-24= -4
It is false
Now plug x= -2
8(-2)=2(-2)+2
-16 = -4+2
-16 = -2
This is false
Now plug x= -1
8(-1)=2(-1)+2
-8 = -2+2
-8=0
It is false
Now plug x= 0
8(0)=2(0)+2
0=0+2
0=2
It is false
Now plug x= 1
8(1)=2(1)+2
8=2+2
8=4
False
Now plug x= 2
8(2)=2(2)+2
16=4+2
16=6
False
Now plug x=3
8(3)=2(3)+2
24=6+2
24=8
It is false
It means there is no solution to 8x=2x+2 for the integers values of x between −3 and 3
Part C:
Plot the two given functions on a coordinate plane and identifying the point of intersection(values of the variables which satisfy both equations at a particular point) of the two graphs.
The graph is attached. The point of intersection at x =0.333 and value of y = 2.667....
Answer:
Step-by-step explanation:
I assumed that the numbers after the spaces were powers. This question was rather unclear.