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3 years ago

Six less than the product of a number n and 1/5 is no more than 99

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

5 0

Answer:

(n * ⅕) - 6 ≤ 99

Step-by-step explanation:

Translating the word problem into an algebraic expression, we have;

(n * ⅕) - 6 ≤ 99

Opening the bracket, we have;

n/5 - 6 ≤ 99

Rearranging the equation, we have;

n/5 ≤ 99 + 6

n/5 ≤ 105

Multiplying both sides by 5, we have;

5 * n/5 ≤ 105 * 5

n ≤ 525

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What are the roots of x cubed - 7*x squared + 13x-6

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The roots of x^3 - 7x^2 + 13x - 6 are 0.697, 2 and 4.303

<h3>How to determine the roots?</h3>

The expression is given as:

x^3 - 7x^2 + 13x - 6

Express as a function

f(x) = x^3 - 7x^2 + 13x - 6

Next, we plot the graph of the function f(x) (see attachment)

From the attached graph, we have the zeros to be:

x = 0.697, 2 and 4.303

Hence, the roots of x^3 - 7x^2 + 13x - 6 are 0.697, 2 and 4.303