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natta225 [31]
3 years ago
15

Write the equation of line -2,5 and 5,-2

Mathematics
1 answer:
love history [14]3 years ago
3 0

Answer:

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(-2,5) and (5,-2).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-2,5), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-2 and y1=5.

Also, let's call the second point you gave, (5,-2), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=5 and y2=-2.

Now, just plug the numbers into the formula for m above, like this:

m=  

-2 - 5

5 - -2

or...

m=  

-7

7

or...

m=-1

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-1x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-2,5). When x of the line is -2, y of the line must be 5.

(5,-2). When x of the line is 5, y of the line must be -2.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-1x+b. b is what we want, the -1 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-2,5) and (5,-2).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(-2,5). y=mx+b or 5=-1 × -2+b, or solving for b: b=5-(-1)(-2). b=3.

(5,-2). y=mx+b or -2=-1 × 5+b, or solving for b: b=-2-(-1)(5). b=3.

See! In both cases we got the same value for b. And this completes our problem.

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Dale works at a mattress store, and makes a salary plus commission. He has a $500 weekly salary and makes a 5% commission for sa
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Answer:

1.  \( f\circ g(x)=0.05x-150

2. \( g\circ f(x)=0.05x-3000

3. The first one represents Dale's commission

Explanation:

1. The composition of the function

                                                             \( f\circ g(x)=f(g(x)) \)    

means that you first apply the function g(x) and then f(x) on the output of g(x).

That is:

  • f(x) = 0.05x
  • g(x) = x - 3000

       f(g(x)=0.05(x - 3000)

       f(g(x))=0.05x-150

2. The composition of the function

                                                             \( g\circ f(x)=g(f(x)) \)                                                                  

means that you first apply the function f(x) and then g(x) on the output of f(x).

That is:

      g(f(x))=((0.05x)-3000)=0.05x-3000

3. Which one represents Dale's commission

To calculate Dales's commision you must subtract $3,000 from the sales, to find the sales over $3000. That is: x - 3,000, which is the function g(x).

Therefore, you first use g(x).

Then, you must multiply the output of g(x) by 0.05 to find the 5% of the sales over $3,000. That is: 0.05(g((x)) = 0.05(x - 3000) = 0.05x - 150.

Therefore, the composition that represents Dale's commission is the first one:

  f(g(x)=0.05(x - 3000)

       f(g(x))=0.05x-150

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Step-by-step explanation:

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