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3 years ago

How would i get the area and perimeter of this?

Mathematics

2 answers:

Olin [163]3 years ago

8 0

Answer:

Perimeter would be: 10.1 m

Area would be: 3.08 m

Step-by-step explanation:

To find the perimeter, you just focus on the solid lines. Right now, that's 4.7, 2.2, and 3.2. You add all of those together and you have the perimeter.

To find the area, you have to do something a little different. Right now, you only focus on the base (2.2) and the dotted line (2.8). When you multiply those together, you get, 6.16. If we only did that though, we would be finding the area for a rectangle. For triangles, you always divide by two at the end, since 2 triangles make up a quadrilateral.

6.16/2=3.08

I hope this helped you. If you have any other questions, feel free to ask! :)

Dmitry [639]3 years ago

4 0

Answer:

Perimeter: 10.1 m

Area: 6.16 m^2

Step-by-step explanation:

For perimeter just add up all the sides except for 2.8 m since that is set aside for area.

For area multiply the length 2.2 by the height 2.8 m. The reason behind this is that using a slanted height makes know sense sine when you measure things they should be perfectly as possible vertical

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2 years ago

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lina2011 [118]

Answer:

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2 years ago

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PLEASE HELP- I NEED CORRECT ANSWER!!

Sergio [31]

Answer:

y > 4x + 2

Step-by-step explanation:

Y is above the line so the value has to be greater than the line (or equal to, possibly). So it represents > or ≥

A dotted/dashed line is non-inclusive, so it represents < or >.

Since it is both above the line AND non-inclusive, we would use this sign:

and this equation :)

y > 4x + 2

<em>Have a nice day. Feel Free to ask questions. Spread the Love.</em>

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2 years ago

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The automobile assembly plant you manage has a Cobb-Douglas production function given by p = 10x^0.2 y^0.8

Zepler [3.9K]

Answer:

The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.

This value of Δy is not constant for a constant increase in production.

Step-by-step explanation:

We know that the production function is $p = 10x^{0.2} y^{0.8}$ , and in the current situation $p=1200$ and $x=130$ .

With this information we can calculate the actual budget level:

$p_0 = 10x^{0.2} y^{0.8}\\\\1200=10*130^{0.2} y^{0.8}\\\\1200=26.47*y^{0.8}\\\\y=(1200/26.47)^{1/0.8}=45.33^{1.25}=117.62$

The next year, with an increase in demand of 100 more automobiles, the production will be $p_1=1300$ .

If we calculate y for this new situation, we have:

$y_1=(\frac{p_1}{10x^{0.2}} )^{1.25}=(\frac{1300}{26.47} )^{1.25}=49.10^{1.25}=130$

The budget for the following year is 130.

The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.

$\Delta y=y_1-y_0=130.00-117.62=12.38$

This value of Δy is not constant for a constant increase in production.

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2 years ago

What is the quadratic formula?

Ne4ueva [31]

Answer:

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Step-by-step explanation:

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2 years ago