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3 years ago

Convert 0.865 from Base 10 to Base 2.8 and 16.

Mathematics

1 answer:

svetlana [45]3 years ago

3 0

Answer:

Don't know

Step-by-step explanation:

can't help u in this

sorry

I am from India what about you I think Canada because I choose in states Canada

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What property is this? -9+(4+x) =(-9+4)+x

wlad13 [49]

Answer:

Associative Property

Step-by-step explanation:

The associative property lets us change the grouping, or move grouping symbols (parentheses).

3 0

3 years ago

-12 (-5/6) (-2/15) How do I solve this question I am stuck on an assignment

koban [17]

If a number in parenthesis is directly next to a number without, then the two numbers need multiplied.

-12(5/6)(-2/15) is an example of a double multiplication. But we'll multiply -12 and 5/6 first, then multiply the product by -2/15.

-12x5/6=14 2/5

14 2/5x-2/15=-1 23/25

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hope it helps

sorry if it doesn't

6 0

3 years ago

The perimeter of quadrilateral JKLM is 90 centimeters. Which is the length of side Kl?

Margaret [11]

It would be 16.5. hope this helps

3 0

4 years ago

Read 2 more answers

What is the mean, median, and mode of 3,8,13,4,9,15,7,8,5,

Stella [2.4K]

Answer:

Mean: 8

Median: 8

Mode: 8

Step-by-step explanation:

Find the average

Mean: 3 + 4 + 5 + 7 + 8 + 8 + 9 + 13 + 15 = 72

Divide by the amount on numbers: 72 / 9 = 8

8 is the average

Find the middle

Median: 3, 4, 5, 7, 8, 8, 9, 13, 15

8 is the middle

Find the most common

Mode: 3, 4, 5, 7, 8, 8, 9, 13, 15

8 is most common

3 0

3 years ago

Read 2 more answers

Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten

serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

$\frac {dN}{dt}\propto -N$

$\Rightarrow \R\frac {dN}{dt}=-\lambda N$

$\Rightarrow \frac {dN}N=-\lambda dt$

Integrating both sides

$\Rightarrow \int \frac {dN}N=\int-\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$ln|N_0|=-\lambda .0+c$

$\Rightarrow c=ln|N_0|$

$ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$

Decay equation:

$ln|\frac{N}{N_0}|=-\lambda t$

Given that, the half life of of element X is 11 minutes.

For half life, $N=\frac12 N_0$ , t= 11 min.

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11$

$\Rightarrow ln|\frac12}|=-\lambda . 11$

$\Rightarrow -\lambda . 11=ln|\frac12}|$

$\Rightarrow \lambda =\frac{ln|\frac12|}{-11}$

$\Rightarrow \lambda =\frac{ln|2|}{11}$ [ $ln|\frac12|=ln|1|-ln|2|=-ln|2|$ , since ln|1|=0]

N=154 grams, $N_0$ = 870 grams, t=?

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t$

$\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}$

=27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0

3 years ago

Convert 0.865 from Base 10 to Base 2.8 and 16.​

Convert 0.865 from Base 10 to Base 2.8 and 16.