Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
Hey there!
I think that it safe to say that this room is a rectangular prism. Therefore, the top and bottom (floor and ceiling) have the same area. We see that our floor dimensions are 12 cm long and 7 cm wide. This also applies to the ceiling. Let’s take our two sides and multiply then to find our area.
12(7)=84
Therefore, the area is 84 square centimeters.
I hope that this helps!
Answer:
1/4 times 2 is 0.5
Sarah has 1/2 pounds of clay.
x ≥ 11, x ≤ 8.
The equal then part means closed circle.
If we graph this there's a gap from 8 to 11 so there isn't shading in between.
Option 4 is correct.
Answer:
p║q hence proved.
Step-by-step explanation:
In the question given parameters are line l║m and ∠1 = ∠3
and we have to prove p║q.
Since ∠1 = ∠3 (given)
Opposite angle of ∠1 = ∠2 (Alternate interior angles)
Therefore ∠2 = ∠3 (Transitive property)
∠2 = ∠3 are congruent when lines p and q are parallel and lines l and m are transverse.
Therefore p║q.
Hence proved.