First we calculate how many ways you can choose four books from a set of eight.
We use the formula n! / [r! * (n-r)!]
8! / [4! * 4!]
= 8*7*6*5 / 4*3*2*1 = 70 ways
Then we have to calculate how many permutations can be made from 4 objects which equals 4*3*2*1 = 24
So, the TOTAL number of ways = 70 * 24 = 1,680
Answer:
-8
Step-by-step explanation:
When you factor, you just find two numbers that add to be the first number (16) and multiply to be the second number (64). 8 and 8 both do this. So when we factor, we also add the variable into each equation because it also has been divided into two equations, and we get: (p + 8)(p +8). Notice that the equations are "+8" and not "-8" because two +8s add to give us a +16 and multiply to give us a +64. After that, we just solve the two equations to find the solutions. Subtract 8 from each equation (we do the opposite operation because 8 is positive) to get -8. Because the answer for each equation is the same our answer is -8.
Answer:
n = 5
Step-by-step explanation:
Since this is a right triangle, we can use trig
tan theta = opp /adj
tan 30 = n / 5 sqrt(3)
5 sqrt(3) tan 30 = n
5 sqrt(3) * 1/ sqrt(3) = n
5 = n
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
</span></span>sin<span>θ = (-sqrt3)/2
</span><span><span>θ = 4pi/3, 5pi/3
</span></span><span><span>Therefore the answer is A.
</span></span>
Answer:
10
Step-by-step explanation:
X = -1 so, we have:
3·1² + 1
3² + 1
9 + 1
10
