Answer: cos²(θ) + sin(θ)sin(e)
<u>Step-by-step explanation:</u>
sin (90° - θ)cos(Ф) - sin(180° + θ) sin(e)
Note the following identities:
sin (90° - θ) = cos(x)
sin (180° + θ) = -sin(x)
Substitute those identities into the expression:
cos(x)cos(x) - -sin(x)sin(e)
= cos²(x) + sin(x)sin(e)
Here, we want to check for the relationship between the image and its pre-image
The pre-image is (x,y)
The image is (3x,3y+5)
As we can see, the pre-image is not similar
This is because the transformation applied to the two values are not same
Thus, we have that;
No, the image is not similar to the pre-image as the translations applied to both coordinates are not same
The pre-image was transformed by dilating the x-coordinate of the pre-image by 3 units while the y-coordinate was transformed by dilating the y-coordinate of the pre-image by 3 and translating it upward by 5 units
Answer:
Im not sure but i did 5x9=45
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
m²+8m=0
Factor out an m
m(m+8) =0
Using the zero product property
m=0 m+8 =0
m =0 m=-8
Width: x
Length: 1/6x-1
Perimeter
=x+x+1/6x+1/6x-1-1
=14/6x-2
=7/3x-2