Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
raha of my life with the exception in my case the first two of the year old one is that it will help you are not able the first of
Answer:
i don't now
Step-by-step explanation:
Sorry I couldn't help you
Answer:
5 marbles are black.
Step-by-step explanation:
7-2=5
