L=2W-4
PERIMETER=2L+2W
58=2(2W-4)+2W
58=4W-8+2W
58=6W-8
6W=58+8
6W=66
W=66/6
W=11 ANS. FOR THE WIDTH.
L=2*11-4
L=22-4
L=18 ANS. FOR THE LENGTH.
PROOF:
58=2*18=2*11
58=36+22
58=58
Answer: 1000
Step-by-step explanation:
9 8 1
Hundred tens one
The question is asking for to round to the nearest hundred (100) which means is rounding to [9] in this question.
The number of the place before the hundreds place is [8] on the tens place.
- When numbers are greater than or equal to 5, you round up a digit.
- When numbers are less than 5, you round down a digit.
[8] is greater than 5, so you round 9 up. When rounding 9 up, you get 10.
<h2>So, the final number will be 1000</h2>
Answer:
Option A is correct.
Step-by-step explanation:
We are given the expression:
w(x) = (x+125)^1/3
We need to find w(50)
Putting x = 50 in the above equation
w(x) = (x+125)^1/3
w(50) = (50+125)^1/3
w(50) = (175)61/3
w(50) = 5.59
w(50) = 5.6
So, Option A is correct
Y=-2x-2 is the right answer
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
