An envelope is 6 cm longer than it is wide. The area is 72 cm squared, find the length and the width.
1 answer:
You might be interested in
Answer:
The probability that the final settlement amount is between 1 and 3 given that the initial claim is 2 = (2/9) = 0.2222
Step-by-step explanation:
The complete question is presented in the attached image to this solution
The joint probability distribution is given as
f(x, y) = {2/[x²(x - 1)} × y^-[(2x-1)/(x-1)] for x>1 And y>1
Given that the initial claim estiamted by the comapny is 2, determine the probability that the final settlement amount is between 1 and 3.
That is, x = 2, and y ranges from 1 to 3
Inserting x = 2 into the expression, we obtain
f(y) = (1/2) × y⁻³ = (y⁻³/2)
The required probability would then be
P(1 < y ≤ 3) = ∫³₁ f(y) dy
= ∫³₁ (y⁻³/2) dy
= [y⁻²/-4]³₁
= [3⁻²/-4] - [1⁻²/-4]
= (-1/36) - (-1/4)
= (1/4) - (1/36)
= (8/36)
= (2/9) = 0.2222
Hope this Helps!!!
Answer:
The side of square A is 30 cm.
Step-by-step explanation:
Given that,
The dimensions of square A are three times the dimensions of square B.
The area of square A is 900 sq cm.
Side of square A = 3( side of square B)
Let the side of square B is b. So,
Side of square A, a = 3b
We know that, the area of square is side². So,
Side of square A, a = 3(10) = 30 cm
Hence, the side of square A is 30 cm.