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Vaselesa [24]
3 years ago
8

Which of the b values satisfy the following inequality?

Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

b and c

Step-by-step explanation:

so to answer this one we just plug in all of the answer choices to see which ones satisfy the inequality

for a we plug in b and get 5<8-3 or 5<5 which is not true so it cant be a

next we plug in 9, 5<9-3 or 5<6 so b is a correct answer

next we plug in 10,  5<10-3 or 5<7 which is correct so c is also a correct answer

hope this helps (:

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There are four red ,four blue, and two green marbles in a bag .if one marble is chosen at random from the bag what is the probab
mina [271]

Answer:

There is a 20% probablity that the marble will be green :)

Step-by-step explanation:

  • There are a total of 10 marbles in the bag. 4 red+4 blue+ 2green=10
  • There are two green marbles out of the 10 marbles.  2/10
  • 2 divided by 10 is .20 or 20%
  • Therefore, there is a 20% probability that the marble will be green.
7 0
2 years ago
Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
7 0
3 years ago
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devlian [24]
You have to isolate the (a) so you multiply the 2/3 by 3/2 and you have to do that to the right side. So -24 times 3/2 equals to -36. Therefore, a=-36. 
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I need help finding this angle! I will mark you if you help!
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It's an acute angle because it's smaller than 90 degrees and isn't a straight line.

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What is measurement ​
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Answer:

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Step-by-step explanation:

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3 years ago
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