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3 years ago

13

Lines DE and AB intersect at point C.

1 answer:

alexandr402 [8]3 years ago

3 0

Answer:

25

Step-by-step explanation:

2x+2+5x+3=180 (angles on a straight line)

7x+5=180

7x=180-5

7x=175

x=25 (dividing both sides by 7)

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-2=-(n-8) need help to answer this

Neporo4naja [7]

The answer is n=10 I already did this

7 0

2 years ago

(Giving brainliest and 20 points)

MariettaO [177]

Answer:

B

Step-by-step explanation:

40+88+15=128+15=143

There are three rectangles that compose this shape. The first one has side lengths of 5 & 8 (l times w=a 5 times 8=40, area of the rectangle is 40). The second one has side lengths of 8&11 (8 times 11=88, area is 88). Final rectangles has side lengths of 16-(8+5) and 5 (16-13=3, 3 times 5=15, Area=15). All three of those rectangles added up is 143 as an area of the figure.

5 0

2 years ago

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

2 years ago

Easy slope question need answer FAST

mars1129 [50]

Answer:

Assuming that the scale is 1, x int: (-4,0), y int: (0,-3)

Step-by-step explanation:

Hope this helps :)

5 0

2 years ago

Read 2 more answers

the length of a rectangle is 9 units more than the width of the rectangle, w. if the width of the rectangle is more than 20 unit

Delvig [45]

Answer:

$W>20$

Step-by-step explanation:

Let

L-----> the length of a rectangle

W---> the width of a rectangle

we know that

$L=W+9$ -----> equation A

$W>20$ -----> inequality B

The inequality B represent the equation that could be used to find the possible values of the width

The solution for the width of the rectangle is all real numbers greater than 20 units

3 0

3 years ago