The appropriate formula is C = 2*pi*r.
Here, C = 2*pi*(50 units) = 100*pi units (answer)
The estimate of the problem would be 1/4 because 6/8- 1/2 you would get 1/4.
~Good Luck!~
Answer: 0.0170
Step-by-step explanation:
Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.
i.e. 

We assume the distribution of amounts purchased follows the normal distribution.
Sample size : n=50
Let
be the sample mean.
Formula : 
Then, the probability that the sample mean is at least $25.00 will be :-

Hence, the likelihood the sample mean is at least $25.00= 0.0170
Answer:
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Step-by-step explanation: