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3 years ago

An ant moves 18 millimeters every 5 seconds

Mathematics

1 answer:

vaieri [72.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

First we need to find their rate of speed.

r = d / t

For ant,

Convert millimeters to inches.

1 inch = 25.4 mm

18 mm = 0.7 inch

r = 0.7 / 5

r = 0.14 inches per second

For beetle,

r = 8 / 3

r = 2.7 inches per second

From the rates, you can tell that the beetle crosses the Garden first.

To know how long it takes for the ant to cross is by dividing the length by the rate.

1 yard = 36 inches

13 yards = 468 inches

468 ÷ 0.14 = 668.5 ≈ 669 seconds

In terms of minutes:

11 minutes and 15 seconds

The ant would cross the garden in 11 minutes and 15 seconds (or 669 seconds up to you).

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3 years ago

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the table above represents what type of function x 0,1,2,3 y -6 , -5 ,2 ,21 a.) linear b.) neither linear or nonlinear c.) linea

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Answer:

Step-by-step explanation:

Given the table

$\begin{array}{ccccc}x&0&1&2&3\\ \\y&-6&-5&2&21\end{array}$

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Since for the same change in x, the change in y is different, given table represents nonlinear function.

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3 years ago

Yvonne is researching the effect of education on annual income. A summary of her research is shown in the table.

asambeis [7]

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3 years ago

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2 in 1

ollegr [7]

1)
2x^2 - 13x - 24 = 0;
the discriminant is : ( - 13 )^2 - 4 * 2 * ( -24 ) = 169 + 192 = 361 = 19^2 => we have two different rational-number solutions ;

2)
[ -2( x + 2 ) - 3( x - 5 ) ] / [ ( x - 5 )( x + 2 ) ] < 0 <=>

( -5x + 11 ) / [ ( x - 5 )( x + 2 ) ] < 0

We have 2 situations :
a) - 5x + 11 < 0 and ( x - 5 )( x + 2 ) > 0 => x∈ ( 11 / 5 , + oo ) and x∈( -oo, - 2 )U
( 5 , + oo ) => x∈( 5, +oo);
b) - 5x + 11 > 0 and ( x - 5 )( x + 2 ) < 0 => x∈(-oo, 11/5) and x∈( -2, 5 ) =>
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Finally, x∈ U (-2, 11 / 5 ) U ( 5, +oo).

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3 years ago

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Answer:

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