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Zarrin [17]
3 years ago
6

Find the difference in simplest form for 3/5-1/7

Mathematics
1 answer:
vitfil [10]3 years ago
6 0

3/5 - 1/7

Find the LCM of 5 and 7 to find equivalent fractions for both fractions

LCM = 35

3/5 = 21/35

1/7 = 5/35

So 21/35 - 5/35 = 16/35

I'm pretty sure that's the simplest form because I can't think of a common factor of 16 and 35 by which to reduce it further.

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What is the answer to this equation 5×.4x=10
oksano4ka [1.4K]

The answer to this equation is x=5.

6 0
3 years ago
Read 2 more answers
Which of the following graphs shows the preimage P(x)=x^2 and the image I(x)=P(1/3x)?
Ksju [112]

Answer:

The picture with the widest graph in red

Step-by-step explanation:

The graph P(x) is the parent graph for all quadratic functions. It has a vertex of (0,0) and has the following points:

x      f(x)

-2      4

-1       1

0       0

1         1

2       4

The image of l(x) = P(1/3x) changes the points of the function to

x      f(x)

-2/3      4/9

-1/3        1/9

0       0

1/3        1/9

2/3       4/9

This makes the graph much wider. The graph with the widest red graph is the graph.

7 0
4 years ago
Read 2 more answers
How do you do this please help me
aleksandr82 [10.1K]
Use PEMDAS

first 36-4 = 32
7^2 = 49
(32/16) - 49 is your answer -47
7 0
3 years ago
Help me i mark brain thing help due in 5 minutes
Dmitry_Shevchenko [17]

Answer:

A: 1

B: 17

C: 26

D: 42

E: 57

Step-by-step explanation:

4 0
3 years ago
HELP ASAP<br> Find the 15th term or the geometric sequence 7, -21, 63,
mihalych1998 [28]
<h3><u>Answer:</u></h3>

33480783

<h2><u>Step-by-step explanation:</u></h2>

<u>Finding the Common Ratio:</u>

We know that the formula for the common ratio of a GP is:

r = aₙ / (aₙ₋₁)        <em>(Where n is any integer)</em>

<em>replacing the values, taking n=2</em>

r = -21 / 7

r = -3

<u>Solving for the 15th Term:</u>

We know that the Formula for the nth term of a GP:

G(n) = a * r ⁿ⁻¹     <em>(where a is the first term and r is the common ratio)</em>

<em>replacing the values (taking n = 15 since we need the 15th term)</em>

G(15) = 7 * (-3)¹⁴

G(15) = 33480783

Hence, the 15th term of the given GP is 33480783

5 0
3 years ago
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