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1 year ago

7

Collection of domestic animals is a set. However, a collection of big domestic animal is not a set. How do you justify this stat

ement?

1 answer:

Schach [20]1 year ago

6 0

Collection of domestic animals is a set. However, a collection of big domestic animal is not a set as it is a subset.

<h3>What are Domesticated animals?</h3>

Domestic animals are known to bee dogs, cats, etc. that can live along with humans.

Note that Collection of domestic animals is a set but the collection of big domestic animal is a subset of domestic animals this is because the big domestic animal are part of the domestic animals and as such it will be a subset.

Learn more about animals from

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Which even number is not a composite number 2 4 6 8

sergij07 [2.7K]

2 is not a composite number as it can't be divided rather than 1 or other number.

hope it helps!

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2 years ago

What type of number has exactly two factors

yarga [219]

I'm pretty sure it's a prime number.

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2 years ago

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Help stuck on question number 10

Zolol [24]

Answer:

y = 2/3x - 5 or in standard form 3y = 2x - 5

Step-by-step explanation:

Remember this fact: Parallel lines have the same slope

Step 1 Solve for y so that the equation is in the slope- intersect form

2x - 3y = 6

-3y = -2x + 6

-3y/-3 = -2x/-3 + 6/-3

y = 2/3 x -2

now we know the slope is 2/3 or

when the equation is in Standard form Ax + By = C you can use this fact: slope = - A/B so the slope = -2/-3 = 2/3

Remember the Parallel lines have the same slope

Find the y-intersect "b" use the slope = 2/3 and point (6, -1)

y = mx + b

-1 = 2/3(6) + b

-1 = 4 + b

-5 = b

Now write the equation of line that is parallel to the given line and passes through point (6, -1)

y = 2/3x - 5 or in standard form 3y = 2x - 5

5 0

2 years ago

Consider the quadratic function f(x) = –2x2 5x – 4. the leading coefficient of the function is?

evablogger [386]

Answer:

$\text{-2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

Step-by-step explanation:

Given the quadratic function

$f(x)=-2x^2+5x-4$

we have to find the leading coefficient of given quadratic equation.

$\text{The general form of quadratic equation is }ax^2+bx+c=0$

The coefficient of $x^2$ i.e a is known as the leading coefficient.

Comparing given equation with the standard equation, we get

a=-2

$\text{Hence, -2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

3 0

2 years ago

Read 2 more answers

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago