Answer:
h = 19.6 ft
Step-by-step explanation:
Given that,
A 20 ft ladder 4ft from the base of the wall.
The height of the ladder, H = 20 ft
The base distance, b = 4 ft
We need to find the height of the reach. Let it is P.
Using Pythagoras theorem,
![H^2=b^2+P^2\\\\P=\sqrt{H^2-b^2}\\\\P=\sqrt{20^2-4^2}\\\\=19.59\ ft](https://tex.z-dn.net/?f=H%5E2%3Db%5E2%2BP%5E2%5C%5C%5C%5CP%3D%5Csqrt%7BH%5E2-b%5E2%7D%5C%5C%5C%5CP%3D%5Csqrt%7B20%5E2-4%5E2%7D%5C%5C%5C%5C%3D19.59%5C%20ft)
or
P = 19.6 ft
So, the height is 19.6 ft.
if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation
![\bf 0 = (x+4)(x-2)\implies \begin{cases} 0=x+4\implies &-4=x\\ 0=x-2\implies &2=x \end{cases}](https://tex.z-dn.net/?f=%5Cbf%200%20%3D%20%28x%2B4%29%28x-2%29%5Cimplies%20%5Cbegin%7Bcases%7D%200%3Dx%2B4%5Cimplies%20%26-4%3Dx%5C%5C%200%3Dx-2%5Cimplies%20%262%3Dx%20%5Cend%7Bcases%7D)
now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.
well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys
-4------------(-1)------------2
so the vertex is at x=-1, namely the axis of symmetry is x = -1.
The EXACT ratio is 7.7:1, but you can round it up to about 8:1
Answer:
There is not enough information to answer, you did not say measurements of both drinks.
Step-by-step explanation: