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2 years ago

Here is an illustration of a bedroom. the striped wall and the floor intersect at a

Mathematics

1 answer:

EleoNora [17]2 years ago

3 0

Really don’t know WTH u saying lol

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Determine if the lines r1(t) = <3, 0, 2> + t <1, 2, −2> and r2(s) = <0, 1, −1> + s <4, 1, 1> intersect,

Temka [501]

Answer:

Yes lines are intersecting, point of intersection is <4,2,0>.

Step-by-step explanation:

Given parametric equations of line are:

$r_{1}(t) = + t \\ r_{1}(t) = \\ r_{1}(t) = ---(1)$

$r_{2}(s) = + s \\ r_{2}(s) = \\ r_{2}(s) = ---(2)\\$

If lines are intersecting then parametric coordinates of (1) are equal to (2)

$3+t=4s---(A)\\2t=1+s---(B)\\2-2t=s-1---(C)\\$

Considering A and B to find values of t and s

From A

t=4s-3---(D)

Putting in (B)

2(4s-3)=1+s

8s-6=1+s

7s=7

s=1

Then

t=4-3

t=1

If lines are intersecting then these values of s and t must satisfy (C)

2-2(1)=1-1

0=0

This shows lines are intersecting.

At this value of t, (1) becomes

$r_{1}(1) = \\=$

Putting s=1 in (2)

$r_{2}(1)=4, 1+1,-1+1>\\=$

Point of intersection is <4,2,0>.

4 0

3 years ago

A restaurant earns $1073 on Friday and $1108 on Saturday. Write and solve an equation to find the amount xx (in dollars) the res

alekssr [168]

You start by adding 1073 and 1108 together to get 2181 then subtract 2181 from the 3 thousand to get 819. the restaurant needs to earn 819 dollars (as a minimum) on Sunday.

3 0

4 years ago

there are 4 aces and 4 kings in a standard deck of 52 cards. you picking card random. what is the probability of selecting an ac

Mkey [24]

Probability of an Ace= 4/52
Probability of a King = 4/52

Probability of an Ace or a King = P(Ace) + P(King)
=4/52 +4/52
=8/52
=2/13

8 0

3 years ago

At 55 mph it will take you approximately _____ feet to stop the car. A. 5 feet B. 100 feet C. 228 feet

ololo11 [35]

Answer:

The correct answer is option C, 228 feet

Step-by-step explanation:

As per Newton’s third law of motion:

V2 – U2 = 2 x a x S

Where V = final velocity

U = Initial Vlocity

a = acceleration (-ve)

S= distance travelled

V= 0 mph

U= 55 mph = 80.6667 ft /sec

0 – (80.6667 ft /sec)2 = 2 x (-g/2) x S

S = (80.6667 ft /sec)2 /(32.2 feet per second per second x0.5)

S = 202.1 feet

So the most nearest option is option C

6 0

3 years ago

74% of freshmen entering public high schools in 2006 graduated with their class in 2010. A random sample of 81 freshmen is selec

Assoli18 [71]

Answer: Probability that the proportion of students who graduated is greater than 0.743 is P = 0.4755

Step-by-step explanation:

Given that,

Probability of freshmen entering public high schools in 2006 graduated with their class in 2010, p = 0.74

Random sample of freshman, n = 81

Utilizing central limit theorem,

$P(\hat{p}$

So,

$(P(\hat{p}>0.743) = P(Z>0.743 - \frac{0.74}{\sqrt{\frac{0.74(1-0.74)}{81} } } )$

= P( Z > 0.0616)

= 0.4755 ⇒ probability that the proportion of students who graduated is greater than 0.743.

7 0

3 years ago