Question

Evaluate the expression. StartFraction 9 factorial Over 3 factorial EndFraction 3 6 60,480 362,874

Answer 1

Answer:

60,480 is the correct answer.

Step-by-step explanation:

First of all, let us have a look at the formula of factorial of a number 'n':

$n! = n \times (n-1) \times (n-2) \times ...... \times 1$

i.e. multiply n with (n-1) then by (n-2) upto 1.

Keep on subtracting 1 from the number and keep on multiplying until we reach to 1.

So, $9!$ can be written as: $9 \times 8 \times 7 \times ...... \times 1$

Similarly $3!$ can be written as: $3 \times 2 \times 1$

Re-writing $9 !$ :

$9 \times 8 \times 7 \times ...... 3 \times 2 \times 1\\\Rightarrow 9 \times 8 \times 7 \times ...... 3 !$

Now, the expression to be evaluated:

$\dfrac{9!}{3!} = \dfrac{9 \times 8 \times 7 \times ..... \times 3!}{3!}\\\Rightarrow 9 \times 8 \times 7 \times 6 \times 5 \times 4\\\Rightarrow 60480$

Answer 2

Answer:

60480

Step-by-step explanation: