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3 years ago

6th grade math. :) help me please

Mathematics

2 answers:

zalisa [80]3 years ago

4 0

Answer:

$8\frac{3}{4}$

Step-by-step explanation:

To write as a mixed number means that you will have a whole number and a fraction together. To find the mixed fraction version, see how many times the denominator (bottom) fits into the numerator (top) evenly.

4, 8, 12, 16, 20, 24, 28, 32, 36

1 2 3 4 5 6 7 8 9

4 can go into 35 '8' times without being greater than the numerator. 8 is the whole number. Now subtract the original numerator by the product of 4 and 8, which is 32:

$35-32=3$

3 is the new numerator. Keep the same denominator. Insert all values:

$\frac{35}{4}=8\frac{3}{4}$

:Done

gladu [14]3 years ago

3 0

Answer:

8 3/4

Step-by-step explanation:

The decimal 3.5 as an improper fraction is 35/10.

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neonofarm [45]

Shoshanna is not correct
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3 years ago

Factor completely 3x - 12. (1 point)

yarga [219]

Answer:

3(x - 4)

Step-by-step explanation:

Given

3x - 12 ← factor out 3 from each term

= 3(x - 4)

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3 years ago

Choose the graph which displays the equation.<br><br>y=5x+1

den301095 [7]

Answer: Reference the picture

Step-by-step explanation:

y=mx + b

b is the y intercept (1)

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4 0

3 years ago

What is the value of the expression 1/7 divided by 5 ?

True [87]

Answer:

It would be 1/35.

Step-by-step explanation:

You turn 5 into 1/5 and then multiply 1/7 with 1/5, which is 1/35.

8 0

3 years ago

The domain of u(x) is the set of all real values except 0 and the domain of v(x) is the set of all real values except 2. What ar

Liula [17]

Answer: the restrictions on the domain of (u°v) (x) are x ≠ 2 and which v(x) ≠ 0.

Justification:

1) the function (u ° v) (x) is u [ v(x) ], this is, you have to apply first the function v(x) whose argument is (x), and later the function u (v(x) ) whose argument is v(x).

2) So, the domain of the composed function (u ° v) (x) has to take into account the values for which both functions are defined.

3) The domain excludes x = 2 because v(x) is not defined for x = 2.

4) And the domain must also exclude v(x) = 0 because u is not defined for v(x) = 0.

5) So, in conclusion, the domain is all the real values except x = 2 and the x for which v(x) = 0.

Therefore the resctrictions are x ≠ 2 and v(x) ≠ 0

5 0

3 years ago

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