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Elan Coil [88]
3 years ago
12

List smallest to geatist 0.83, 0.6, 0.7?

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0
Snallest to the greatest
0.6, 0.7, 0.83
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Can someone pls help me with this answer!
ladessa [460]

Answer:

3.5<2

2>3.5

Step-by-step explanation:

5 0
4 years ago
Which ordered pair
rusak2 [61]

Answer:

B)  (-6,5)

Step-by-step explanation:

Quadrant I:  (+,+)

Quadrant II: (-,+)

Quadrant III: (-,-)

Quadrant IV: (+,-)

3 0
4 years ago
Find the values of m &amp;n .. please help !!
matrenka [14]

Answer:

m = 12.728 or 18/root (2)/2, n = 9

Step-by-step explanation:

To find m, we can use sin(45) and cos(45).

Since sin(45) = root (2)/2  and this equals 9/m.

We set the equation root (2)/2  = 9/m and solve for m.

9 divided by root (2)/2 would give us 18/root (2), or 12.728.

m is 12.728.

Same process for n but we are using cosine this time.

cos(45) = root (2)/2 and this equals n/12.728.

Solving for n would give us root (2)/2 times 12.728.

This gives us that n is 9.

6 0
3 years ago
Solve for x x−3/11=8<br><br>x=​
LiRa [457]
What huh? I don’t rly understand
4 0
3 years ago
In bioligy class cher is viewing cells with a microscope. cell h measures 8.76x10^-3 microns in diameter and cell v measures 2.1
3241004551 [841]

Answer:

Larger cell 400 times  bigger cell than the smaller cell

Step-by-step explanation:

Given:

diameter of the cell h =  8.76\times10^{-3}

diameter of the cell v  =2.19 \times10^{-5}

To Find:

How many tines larger is the bigger cell than the smaller cell?

Solution:

The  cell h with diameter   8.76\times 10^{-3} is larger and the cell v with diameter 2.19 \times 10^{-5} is small. To find the number of times it is larger,  we can divide the larger cell diameter by smaller cell diameter

=>\frac{8.76\times 10^{-3}}{2.19 \times 10^{-5}}

=>\frac{8.76\times 10^ {-3} \times 10^{5}}{2.19 }

=>\frac{8.76\times 10^ {(-3+5)}}{2.19 }

=>\frac{8.76\times 10^2}{2.19 }

=>\frac{876}{2.19}

=> 400

Larger cell is the bigger cell than the smaller cell by 400 times

6 0
3 years ago
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