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Crazy boy [7]
3 years ago
15

What is an equation of the line that is perpendicular to y-4=2(x-6) and passes through (-3,-5)

Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0

Answer:

y = -1/2 x - 13/2

Step-by-step explanation:

what is an equation of the line that is perpendicular to y-4=2(x-6) and passes through (-3,-5)

First, we need the slope of the given line.

y - 4 = 2(x - 6)

y - 4 = 2x - 12

y = 2x - 8

The slope of the given line is 2.

The slopes of perpendicular lines are negative reciprocals, so the slope of the perpendicular is -1/2.

y = -1/2 x + b

We use the given point as x and y and solve for b.

-5 = -1/2(-3) + b

-10 = 3 + 2b

2b = -13

b = -13/2

The equation of the perpendicular line is:

y = -1/2 x - 13/2

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Explanation:
The equation of a line in
slope-intercept form
is.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
∣
2
2
y
=
m
x
+
b
2
2
∣
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−−−−−−−−−−−−−−−

where m represents the slope and b, the y-intercept.
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4
x
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into this form
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4
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x
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y
=
−
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x
+
1
⇒
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=
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