Question

What is an equation of the line that is perpendicular to y-4=2(x-6) and passes through (-3,-5)

Answer 1

Answer:

y = -1/2 x - 13/2

Step-by-step explanation:

what is an equation of the line that is perpendicular to y-4=2(x-6) and passes through (-3,-5)

First, we need the slope of the given line.

y - 4 = 2(x - 6)

y - 4 = 2x - 12

y = 2x - 8

The slope of the given line is 2.

The slopes of perpendicular lines are negative reciprocals, so the slope of the perpendicular is -1/2.

y = -1/2 x + b

We use the given point as x and y and solve for b.

-5 = -1/2(-3) + b

-10 = 3 + 2b

2b = -13

b = -13/2

The equation of the perpendicular line is:

y = -1/2 x - 13/2