For this case we have the following equation:
x ^ 2-2x-4 = 0
We use the quadratic formula:
x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
Substituting values we have:
x = (- (- 2) +/- root ((- 2) ^ 2 - 4 * (1) * (- 4))) / (2 * (1))
Rewriting we have:
x = (2 +/- root (4 + 16)) / 2
x = (2 +/- root (20)) / 2
x = (2 +/- root (4 * 5)) / 2
x = (2 +/- 2raiz (5)) / 2
x = (1 +/- root (5))
The roots are:
x1 = (1 + root (5))
x2 = (1 - root (5))
Answer:
x1 = (1 + root (5))
x2 = (1 - root (5))
Hello,
10 is not a digit!
Let' a ,b ,c the 3 digits
Numbers are
10a+b
10a+c
10b+c
10b+a
10c+a
10c+b
sum = 22a+22b+22c=22(a+b+c)
sum /(a+b+c)=22
Answer:
??
Step-by-step explanation:
Answer:
It's C
Explanation: I don't need to give you an explanation >:(
Let's assign the width to a variable, with that variable being x. the length is two times the width, so it would be 2x. the perimeter of a rectangle is length + length + width + width, so you would add 2x + 2x + x + x = 24 inches. combine like terms (x) to get 6x = 24. divide both sides by 6 to get x = 4. so the width (x) is 4, and the length (2x) is 8. the area of a rectangle is length times width, so multiply 4 * 8. that would get you 32 inches^2.
