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Andreas93 [3]
3 years ago
7

What is an equation of the line that passes through the points (1,1) and (7,-5)

Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

y=-x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)=(-5-1)/(7-1)=-6/6=-1

y-y1=m(x-x1)

y-1=-1(x-1)

y-1=-x+1

y=-x+1+1

y=-x+2

mojhsa [17]3 years ago
7 0

Answer:

y=-1x+2

Step-by-step explanation:

m=  

-5 - 1 over 7 - 1

(1,1). y=mx+b or 1=-1 × 1+b, or solving for b: b=1-(-1)(1). b=2.

(7,-5). y=mx+b or -5=-1 × 7+b, or solving for b: b=-5-(-1)(7). b=

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