Answer:
B. Yes, the proportion of girls is significantly different from 0.5
Step-by-step explanation:
Given that a clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 340 babies wereborn, and 306 of them were girls.
Sample proportion = 
Std error of p = 
For sample size large, we find that t distribution almost coincides with z distribution
Hence 99% critical value = 2.58
Margin of error = 2.58*std error = 0.0420
Confidence interval = 
=
0.858<p<0.942
Yes, this method is effective becuse lower bound itself is 0.858 i.e. there is 85.8%chance for getting girls in birth
B. Yes, the proportion of girls is significantly different from 0.5
Answer:
-2/1
Step-by-step explanation:
Rise over run. The line goes up 2 blocks, and over 1. It's a negative because The line is going downward.
<span>So we want to know which of theese products are negative. We have three rules: -1*(+1)=-1 and -1*(-1)=+1 and +1*(+1)=+1 Lets calculate and check: A. is negative, B. is negative, C. is positive and D.positive. So Aand B are negative and that is the correct answer.</span>
Answer:
101.4
Step-by-step explanation:
13% of 780 is 101.4
Hope this helps you:)
Answer:
Option D
Step-by-step explanation:
A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and constructs a 99% confidence interval for the true mean finish time to be (86.05, 99.38) minutes.
Assuming the reporter performed the calculations correctly, which of the following statements are appropriate interpretations of this confidence interval?
We can expect that 99% of confidence intervals created using the same method the reporter used will contain the true mean run time for runners of this race.
