3 years ago

Find a tenth of three quarters of $800

1 answer:

3 0

I'm pretty sure it's 60 US$

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olya-2409 [2.1K]

Answer:

i think you forgot the rest of the question?

6 0

3 years ago

const2013 [10]

i think 7 but i am not very sure

7 0

3 years ago

elixir [45]

3) 1/1 2/0 -2/0 good luck i hope this helped

3 0

3 years ago

kumpel [21]

Let $a_k$ denote the kth term of the sequence. Then

$a_k=a_1+d(k-1)$

where d is the common difference between consecutive terms in the sequence and a₁ is the first term.

The sum of the first n terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the nth term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago

Ber [7]

Reduce the expressions, if possible by cancelling the common factors.
Exact form: 22/9
Decimal form: 2.4
Mixed Number form: 2 2/9

5 0

3 years ago