Question

Please help I will mark brainliest AOD is 62 degrees btw

Answer 1

Step-by-step explanation:

a)

DA is tangent and at point A and OA is radius of the circle.

$\therefore OA \perp DA\\\therefore \angle OAD = 90°\\In\: \triangle AOD\\m\angle AOD= 180° - (m\angle OAD + m\angle ODA) \\\therefore m\angle AOD= 180° -(90°+28°)\\\therefore m\angle AOD= 180° -118°\\\huge \red {\boxed {\therefore m\angle AOD=62°}} \\\\b) \\\because m\angle ABC = \frac{1}{2} \times m\angle AOD$

(Angle formed at the circumference of the circle is half the angle formed at the center of the circle)

$\therefore m\angle ABC = \frac{1}{2} \times 62°\\\huge \red {\boxed {\therefore m\angle ABC = 31°}}$