All categories

3 years ago

What are the zeros of the function represented by the quadratic expression 2x^2-5x-3

1 answer:

3 0

2x2-5x-3=0

Two solutions were found :

x = -1/2 = -0.500

x = 3

Step by step solution :

Step  1  :

Equation at the end of step  1  :

(2x2 - 5x) - 3 = 0

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  2x2-5x-3

The first term is,  2x2  its coefficient is  2 .
The middle term is,  -5x  its coefficient is  -5 .
The last term, "the constant", is  -3

Step-1 : Multiply the coefficient of the first term by the constant   2 • -3 = -6

Step-2 : Find two factors of  -6  whose sum equals the coefficient of the middle term, which is   -5 .

You might be interested in

Mark runs 3/4 of a mile each day for 5 days. What is the total distance that Mark has run after 5 days? A.3 3/4 B.4 1/4 C.5 3/4

Evgen [1.6K]

3/4 x 5 = 3 3/4

Your answer is A.

6 0

3 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

3 years ago

Pls help. I WILL MARK BRAINLIEST!

goblinko [34]

Answer:

Step-by-step explanation:

because if you look at the line below it it shows 180 degrees because it is a straight line if that makes sense. if not just trust me.

6 0

3 years ago

Read 2 more answers

Jane is is charge of making a banner for the basketball game this Saturday. She measures how long the banner is before painting

RSB [31]

Answer:

The measurement which Jane finds to be 10 meters is the length of the banner.

Step-by-step explanation:

The measurement of 10 meters which Jane found after measuring how long the banner is before painting is the LENGTH of the banner.

This is clear from the unit of what she finds (meters). It only indicates the measurement of one part of the banner, even though a banner has two parts, the length and width.

It is possible to find the AREA, or PERIMETER, or LENGTH.

But what she finds is the LENGTH of the banner. If it was Area or Perimeter, the unit would have been square meters.

7 0

3 years ago

Finding Distance in the Coordinate Plane

GuDViN [60]

The distance between the two points (-1, 4) and (5, 4) is 6 units.

Step-by-step explanation:

The given Coordinate points are (-1, 4) and (5, 4).

The points are considered as (x1,y1) and (x2,y2).

Here,

x1 = -1 and x2 = 5

y1 = 4 and y2 = 4

The distance formula is given by :

Distance = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

To find the distance between these two points :

The distance formula is used,

Distance = $\sqrt{(5+1)^2+(4-4)^2}$

⇒ √(6)²

⇒ √36

⇒ 6

Therefore, the between the points is 6 units.

5 0

3 years ago