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MatroZZZ [7]
3 years ago
13

I WILL AWARD BRAINLIEST!!!! PLEASE HELP!!

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

x= 14

y= 5

Step-by-step explanation:

3x+23+25=90    3x=90-48   x=14

3(14)+23+5y= 90    65+5y=90  y= 5

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What is the value of the expression 3p (4p +5) + 3 for p= -1 is<br>plzzzzzzzz i want it fast
AleksAgata [21]

Answer:

0

Step-by-step explanation

well at least thats my guess!

we have to go by bidmas. so you substitute first!

so its going to be: 3(-1)(4(-1)+5)+3

all I did is that I replaced all p's by -1 and then you multiply it!

so its gonna be: -3(-4+5)+3

you first solve what's in the brackets which is -4+5 so the answer is 1 like this: -3(1)+3 now its much simpler. all we have to do is to expand the bracket so its going to be -3+3 so the answer is 0!

7 0
3 years ago
What is the distance ?
Gwar [14]

Distance between 2 points formula: √(x2 − x1)² + (y2 − y1)²

= √(7 - (-3))² + (-1 - 5)²

= √10² + -6²

= √100 + 36

= √136

≈ 11.662 (Note that this number is rounded because its a a non-terminating decimal).

Best of Luck!

4 0
3 years ago
If / and / are midsegments of , what can you conclude about / and /? Verify your results by finding x when QR = 3x + 2 and NP =
Ad libitum [116K]
Midsegments are line segments that connect the midpoints of a triangle. If we have the condition that QR = NP, we have the equation
3x + 2 = 2x + 16
Solving for x
3x - 2x = 16 - 2
x = 14
Therefore, x is 14. <span />
8 0
3 years ago
What is the probability a sample of 90 test takers will provide a sample mean test score within 10 points of the population mean
Elena-2011 [213]

Answer:

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

Step-by-step explanation:

The following information is missing:

The standard deviation of population is 100.

We are given the following information in the question:

Population mean, μ = 502

Standard Deviation, σ = 100

Sample size, n  = 90

Standard error =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{100}{\sqrt{90}} =  10.54

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(test score within 10 points)

P(492 \leq x \leq 512) \\\\= P(\displaystyle\frac{492 - 502}{10.54} \leq z \leq \displaystyle\frac{512-502}{10.54}) \\\\= P(-0.9487 \leq z \leq 0.9487)\\= P(z \leq 0.9487) - P(z < -0.9487)\\= 0.829 -0.171 = 0.658 = 65.8\%

P(492 \leq x \leq 512) = 65.8\%

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

7 0
3 years ago
Solve 9-3(x+4)=2(x-3)-8<br> A)3<br> B)2.5<br> C)-2.5<br> D)-4
cupoosta [38]

Answer:

x=11/5, or x=2.2.

Step-by-step explanation:

9-3(x+4)=2(x-3)-8

9-3x-12=2x-6-8

9-12-3x=2x-14

-3-3x=2x-14

-3-3x-2x=-14

-3-5x=-14

5x=-3-(-14)

5x=-3+14

5x=11

x=11/5

x=2.2

4 0
3 years ago
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