All categories

3 years ago

Using the numbers -4, 10, 8, 2, -3, -5 create two expressions that equal six

Mathematics

2 answers:

Svetllana [295]3 years ago

8 0

Answer:

-4 +8 +2

2-4+8

Step-by-step explanation:

docker41 [41]3 years ago

3 0

Answer:

8-2 and 10-3

Step-by-step explanation:

You might be interested in

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$

Therefore,

a) $E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]$

$=\sum_{i=1}^{5} \frac{200}{101-i}$

$\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

$b)$

The variance is given by, $\mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]$

$\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

7 0

3 years ago

13. A bakery is having a buy 4, get 1 free sale on cakes. This sale is eguivalent to what percentage off the regular price of al

exis [7]

Answer: 20

Step-by-step explanation:

3 0

3 years ago

HELP PLEASE!!!

boyakko [2]

Depends on if you want it rounded.

14.47

4 0

3 years ago

Anika [276]

Answer:

Step-by-step explanation:

7 0

2 years ago

Simplify:<br><br> Cube root of (128a^13b^6)

Pavlova-9 [17]

$\sqrt[3]{128a^{13}b^{6}} \\\sqrt[3]{64a^{12}b^{6} * 2a} \\\sqrt[3]{64a^{12}b^{6}}\sqrt[3]{2a} \\4a^{4}b^{2}\sqrt[3]{2a}$

7 0

3 years ago