Answer:
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%
Step-by-step explanation:
Let 'M' be the event of selecting males n(M) = 12
Number of ways of choosing 3 students From all males and females
Number of ways of choosing 3 students From all males
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%
<u><em>Final answer</em></u>:-
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%
-5x-12>6x-4
To Solve the inequality we need to get x alone
-5x-12>6x-4
first we remove -12, for that we add 12 on both sides
-5x-12+12>6x-4+12
-5x > 6x +8
Now subtract 6x from both sides
-5x -6x> 6x-6x +8
-11x > 8
Divide by -11. when we divide by -11 we flip the inequality . so > becomes <
We need to give the answer in interval notation.
x is less than -8/11 so x value starts from -8/1 and goes to -infinity(left)
So interval notation is (-∞, )
I believe the answer is 0