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4 years ago

Factor 40x^3-5y^3 COMPLETELY

1 answer:

7 0

$40x^3-5y^3=5(8x^3-y^3)=5[(2x)^3-y^3]\\\\use:a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=5(2x-y)[(2x)^2+2xy+y^2]=5(2x-y)(4x^2+2xy+y^2)$

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A restaurant is offering 2 specials: 10 burritos for $12, or 6 burritos for $7.50. Noah needs 60 burritos for his party. Should

slega [8]

Answer:

6 orders of the 10 burrito special

Step-by-step explanation:

10 burritos for $12

60 burritos for $72.

6 burritos for $7.50

10 burritos for $75

So the 10 burritos for $12 is better.

Hope this helps :D

5 0

3 years ago

determine whether the lines intersect and if so find the point of intersection and the cosine of the angle of intersection x=4t+

Fittoniya [83]

Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

$4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)$

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

$From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0$

Hence the lines are not intersecting nor parallel, they must be skew.

6 0

3 years ago

Can anybody help me please

MatroZZZ [7]

Answer:

○ 4⁄6, -4⁄6

Step-by-step explanation:

Take the square root of both the denominator and numerator, and you will get the above two answers.

I am joyous to assist you anytime.

4 0

3 years ago

If f(x)= x^1/2 - x and g(x)= 2x^3 - x^1/2 - x, find f(x) - g(x)

Pavlova-9 [17]

Answer:

$-2x^3+2x^{1/2}$

Step-by-step explanation:

First, you have to substitute both functions into the equation to get:

$f(x)-g(x) = (x^{1/2}-x) - (2x^3-x^{1/2}-x)$

Then, you distribute the negative sign in front of g(x) to get:

$= x^{1/2} - x -2x^3+x^{1/2}+x$

And finally, you add/subtract the x's that have the same power to get:

$=-2x^3+2x^{1/2}$

3 0

3 years ago

How many solutions does the equation have?

Rus_ich [418]

$2(2x+5)=4(x+3)\\2\times2x+2\times5=4\times x+4\times3\\4x+10=4x+12\ \ \ \ |subtract\ 4x\ from\ both\ sides\\10=12-FALSE\\\\therefore,\ answer\ is\ \boxed{C.\ No\ solution}$

7 0

3 years ago

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