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Hoochie [10]
4 years ago
7

Factor 40x^3-5y^3 COMPLETELY

Mathematics
1 answer:
lianna [129]4 years ago
7 0
40x^3-5y^3=5(8x^3-y^3)=5[(2x)^3-y^3]\\\\use:a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=5(2x-y)[(2x)^2+2xy+y^2]=5(2x-y)(4x^2+2xy+y^2)
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<h3>How to find Scale Factor?</h3>

Scale factor = dimension of new figure / dimension of original figure

The polygons given are shown in the diagram attached below.

Figure A is the original figure

Figure B is the new figure.

x, y, and z has been used to mark the missing sides of figure B.

One dimension of original figure = 15

Corresponding dimension of the new figure = 3

Scale factor = new/original = 3/15

Scale factor = 1/5

To find the missing sides of figure B, multiply each corresponding side lengths of Figure A by the scale factor:

x = 12 × 1/5 = 2.4

y = 18 × 1/5 = 3.6

z = 20 × 1/5 = 4

In summary:

The scale factor is: 1/5.

The missing sides of figure B are: 2.4, 3.6, and 4.

Learn more about scale factor on:

brainly.com/question/2826496

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