Factor 40x^3-5y^3 COMPLETELY

1 answer:

7 0

$40x^3-5y^3=5(8x^3-y^3)=5[(2x)^3-y^3]\\\\use:a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=5(2x-y)[(2x)^2+2xy+y^2]=5(2x-y)(4x^2+2xy+y^2)$

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Answer:

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Step-by-step explanation:

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cupoosta [38]

Answer:

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

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$Z = \frac{X - \mu}{\sigma}$

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In this problem, we have that:

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