4 years ago

Factor 40x^3-5y^3 COMPLETELY

1 answer:

7 0

$40x^3-5y^3=5(8x^3-y^3)=5[(2x)^3-y^3]\\\\use:a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=5(2x-y)[(2x)^2+2xy+y^2]=5(2x-y)(4x^2+2xy+y^2)$

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AveGali [126]

Answer:

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3 years ago

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3 years ago

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$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

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3 years ago

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Blababa [14]

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3 years ago

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Maslowich

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