Factor 40x^3-5y^3 COMPLETELY

1 answer:

7 0

$40x^3-5y^3=5(8x^3-y^3)=5[(2x)^3-y^3]\\\\use:a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=5(2x-y)[(2x)^2+2xy+y^2]=5(2x-y)(4x^2+2xy+y^2)$

You might be interested in

Sergeu [11.5K]

7,14,21,28,35,42 ......................

6 0

4 years ago

Fudgin [204]

Answer:

I can't see the picture.

Step-by-step explanation:

6 0

3 years ago

Flauer [41]

...... 24 is the answer

5 0

3 years ago

Pavlova-9 [17]

I believe b is about 16.3, hope this helps

4 0

3 years ago

Oliga [24]

The common ratio is 2:1, or dividing by 2

3 0

3 years ago