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USPshnik [31]
3 years ago
12

Uma pessoa deseja restaurar seu veículo antigo e para isso deverá contratar serviços mecânico, de funilaria e de autoelétrica. P

ara poder pagar os serviços contratados, a pessoa resolve aplicar o dinheiro em uma aplicação que paga juros compostos de 1,15% a.M. A quantia de R$ 750,00 por mês durante um ano e meio.
Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

CI=P*(1 + R/100)^18

A=(CI + P) = P(1+R/100)^18

13500/P=1(100+R/100)^18

A/P=(100+R/100)^18

A/P=(100+R/100)^18

A=13500$        as (750 * 18)

(13500)/P=(1 +1.15/100)18

(13500)/P=(1+1.15/100)18

13500=((1.0115)^18

P=R$10989.02

Step-by-step explanation:

CI=Compound Interest

A=Amount

P=Principal.

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7 0
3 years ago
The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/
VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

A = \frac{1}{2}bh   (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)

We can find the base by solving equation (1) for b:

b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)

\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min    

         

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7 0
2 years ago
A suit regularly cost 375.95 cents Bob buys it on sale for 268.35 cents how much does he save
Stolb23 [73]

Hello, all we need to do in this case to subtract the amount of money Bob paid for the suit from the amount of money the suit regularly costs. So:

375,95 - 268,35 = 107,6

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Step-by-step explanation:

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[RevyBreeze]

3 0
2 years ago
Read 2 more answers
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