I do not think we need to rewrite the first two numbers in the given above because they are already the simplest forms of themselves being whole numbers. However, the third number may be rewritten as 1/2 by dividing both numerator and denominator by 5 and the last one as 2/25 by dividing both numerator and denominator by 4.
Answer: he should invest $16129 today.
Step-by-step explanation:
Let $P represent the initial amount that should be invested today. It means that principal,
P = $P
It would be compounded annually. This means that it would be compounded once in a year. So
n = 1
The rate at which the principal would be compounded is 7.6%. So
r = 7.6/100 = 0.076
The duration of the investment would be 6 years. So
t = 6
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years.
A = 25000
Therefore
25000 = P(1+0.076/1)^1×6
25000 = P(1.076)^6
25000 = 1.55P
P = 25000/1.55
P = $16129
<u>Given Function is</u>
- f ( x ) = 7x - 7 ------- eqn ( 1 )
<u>Now , put the value of x = 8 in eqn ( 1 )</u>
- f ( 8 ) = 7 ( 8 ) - 7
- f ( 8 ) = 56 - 7
- f ( 8 ) = 49 ------- eqn ( 2 )
<u>Now , put the value of x = 4 in eqn ( 1 )</u>
- f ( 4 ) = 7 ( 4 ) - 7
- f ( 4 ) = 28 - 7
- f ( 4 ) = 21 ------- eqn ( 3 )
<h3 />
<u>From eqn ( 2 ) nd eqn ( 3 ) we get,</u>
- f ( 8 ) + f ( 4 )
- 49 + 21
- 70
Hope Helps! :)
Answer:
There is a total of 45 members in the math club.
Step-by-step explanation:
What I did is I multiplied 9 by 5 and got 45. I multiplied 9 by 5 because the question stated that 9 students are 20%. 20% times 5 would be 100%, which would be the total number of students.
Hope this helped :)
The answer is 1/q^30 because after simplifying, you can cancel out the p and then you get q^q-20 times q^-10 to get q^-30 which then equals 1/q^30
