Question

I need help on number 3 please

Answer 1

Answer:

$\large\boxed{x=10}\\\\\boxed{40^o,\ 50^o,\ 90^o}$

Step-by-step explanation:

We have the right triangle. The sum of the angles measured in the right triangle is 90 °. Therefore we have the equation:

$4x+(6x-10)=90[/tex][tex]4x+6x-10=90$                   add 10 to both sides

$10x=100$           divide both sides by 10

$x=10$

The measure of angles:

Put the value of x to the eqpressions:

$6x-10\to6(10)-10=60-10=50\\\\4x\to4(10)=40$