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otez555 [7]
3 years ago
11

I need help on number 3 please

Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0

Answer:

\large\boxed{x=10}\\\\\boxed{40^o,\ 50^o,\ 90^o}

Step-by-step explanation:

We have the right triangle. The sum of the angles measured in the right triangle is 90 °. Therefore we have the equation:

4x+(6x-10)=90[/tex][tex]4x+6x-10=90  <em>                 add 10 to both sides</em>

10x=100           <em>divide both sides by 10</em>

x=10

The measure of angles:

Put the value of x to the eqpressions:

6x-10\to6(10)-10=60-10=50\\\\4x\to4(10)=40

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Ber [7]
A)
8^2+9^2=c^264+81=c^2
c^2=145c=sqrt 145c=12.04
B)
Pythagerean Theorum: 
A^2+B^2=C^2, where C is the hypotenuse and A and B are the other legs 
15^2=9^2+B^2 
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3 years ago
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ch4aika [34]

Answer:

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Step-by-step explanation:

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Hope this helps have a great day! :)

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