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3 years ago

Evaluate the expression when c=4. c²-9c+8

Mathematics

2 answers:

Nonamiya [84]3 years ago

8 0

Answer:

-12

Step-by-step explanation:

Alex Ar [27]3 years ago

4 0

Answer:

Your answer

Step-by-step explanation:

When c=4. Then,

c²-9c+8

= 4²-9c+8

= 4*4-9c+8

= 16-94+8

= 78+8

= -86 ans

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The line has the same slope as 7x-y=5 and the same y intercept as the graph 3y-11x=15

scoundrel [369]

7x - y= -5. Standard form is when it is written with x and y on the same side, but x is not negative or a fraction. To find the slope and y intercept, you must change the first two equations to slope intercept. You get y=7x-5 for the first one and y=11/3x+5 for the seccond equation. Take the 5 as your y intercept and the 7 as your slope and you get y=7x+5. Now you need to change it into standard form. When all is said and done, your final answer should be 7x - y = -5.

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3 years ago

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Can someone help me with this triangle?? Find missing side lengths

lakkis [162]

Answer:

M= 15 degrees N= 15 degrees

Step-by-step explanation:

Right triangles are always 90 degrees so 90-60=30

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3 years ago

2x - 3 = - ( 4x + 9 )

mafiozo [28]

2x-3 = -(4x+9)

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3 years ago

The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin

quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

So, According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of The inscribed circle

So, the center of The inscribed circle is the point S

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

So, According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of The circumscribed circle

So, the center of The circumscribed circle is the point P

5 0

4 years ago

Can someone please help me with this problem.

iren [92.7K]

X^2 + 3x - 6

This is because x^2 and 3x have nothing they can combine with, leaving them as their own number. 1 + - 6 will give you -5 as adding to a negative only reduces not adds entirely.

Hope this helps!

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3 years ago