Answer:
See Explanation
Step-by-step explanation:
a) Additive inverse of −2
- the additive inverse of a number a is the number that, when added to 'a', yields zero. This number is also known as the opposite (number), sign change, and negation.
- So the Additive inverse of -2 is 2. ∴ -2+2=0
b) Additive identity of −5
- Additive identity is the value when added to a number, results in the original number. When we add 0 to any real number, we get the same real number.
- -5 + 0 = -5. Therefore, 0 is the additive identity of any real number.
c) additive inverse of 3
- Two numbers are additive inverses if they add to give a sum of zero. 3 and -3 are additive inverses since 3 + (-3) = 0. -3 is the additive inverse of 3.
d). multiplicative identity of 19
- an identity element (such as 1 in the group of rational numbers without 0) that in a given mathematical system leaves unchanged any element by which it is multiplied
- Multiplicative identity if 19 is 1 only, since 19 x 1 = 19.
e) multiplicative inverse of 7
- Dividing by a number is equivalent to multiplying by the reciprocal of the number. Thus, 7 ÷7=7 × 1⁄7 =1. Here, 1⁄7 is called the multiplicative inverse of 7.
d) | 11-5|×|1-5|
- | 11-5|×|1-5| ⇒ I6I×I-4I ⇒ 6×4 ⇒ 24
The answer is B . your welcome
Answer:
the locus is the perpendicular bisector of the segment
Step-by-step explanation:
The points equidistant from A and B lie on the line that is the perpendicular bisector of segment AB.
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<em>Comment on this geometry</em>
You take advantage of this fact when you construct a circle through 3 points. You construct the perpendicular bisectors of segments between pairs of the points, and locate the center of your circle at their intersection.
1. the graph of 2x + 1 = y for all real numbers will be a line. the graph with the restricted domain will be a line segment meaning it has endpoints (1, 3) and (4, 9).
2. is open ended, meaning you can make A, B, C anything you want as long as what they specify is met.
(a) A = 0
(0)x + By = C
let's make B = 1 and C = 5
y = 5
(b) B = 0
Ax + (0)y = C
let's make A = 1 and C = 5
x = 5
(c) C = 0
Ax + By = 0
let's make both A and B = 1
x + y = 0
3. plot both intercepts (x on x-axis, y on y-axis) then draw a line through the dots.
4-7. linear equations do not have exponents on any of the variables. 1/y is the same as y^(-1) so both 4 and 7 are non-linear.
8-13. you will have to graph these. put them in slope intercept form: y = mx+b if they're not already , plot the y-intercept first (0, b) then use the slope m draw the line by going rise over run.
example 13.
3x + 4y = 12
4y = -3x + 12
y = (-3/4) + 3
plot (0,3)
go down -3 , right 4 make a point.
reverse from (0,3) go up 3 left -4 and make a point. connect with line.
Answer:
Step-by-step explanation:
I can't read it very well. If it says
5(6n-4)+2=68
30n-20+2=68
30n=86
n= 43/15 or 2 13/15
If it says
5(6n-4)-2=68
30n-20-2=68
30n=90
n= 3
