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kipiarov [429]
2 years ago
7

PLEASE HELP A bag contains red and blue marbles, such that the probability of drawing a blue marble is 3/8 An experiment consist

s of drawing a marble, replacing it, and drawing another marble. The two draws are independent. A random variable assigns the number of blue marbles to each outcome. What is the probability of drawing one blue marble?
Mathematics
2 answers:
jeka57 [31]2 years ago
4 0

Answer:

15/64

Step-by-step explanation:

3 blue

5 red marbles.

since the marble is put back in, the denominator will not change,

so to draw ONE marble, the chances would be

chances of picking a blue marble 3/8

chances of picking a red marble 5/8

3/8 * 5/8 - 15/64

please mark me brainly.

Kay [80]2 years ago
4 0

Answer:

The probability of drawing one blue marble is 3/8 because you have three blue marbles out of a total of eight marbles. The probability of drawing a second blue marble is also 3/8 but since you have to draw both marbles consecutively you have to multiply the probabilities of drawing each marble. So,

3/8•3/8 = 9/64.

Now you need to change it to a percent.

We do this by

9/64 x 100 = 14% approx

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