All categories

3 years ago

Please help me I'm going to be giveng a brainlist to the first person to answer please help me

Mathematics

1 answer:

Oxana [17]3 years ago

3 0

Answer:

The moon is located perpendicular to Earth and the sun.

Step-by-step explanation:

this is what i think but it could be wrong

You might be interested in

Can someone answer these?

Crank

Answer:

#1=3 #2=3 #3=4

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

What is the answer to the question 5/6 * 1/4 = I am having a hard time figuring it out

kotegsom [21]

Answer:

5/24

Step-by-step explanation:

$\frac{5}{6} *\frac{1}{4} =\frac{5*1}{6*4} =\frac{5}{24}$

7 0

3 years ago

Read 2 more answers

A tank contains 60 kg of salt and 1000 L of water. A solution of a concentration 0.03 kg of salt per liter enters a tank at the

charle [14.2K]

Answer:

$\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg$

Step-by-step explanation:

Volume of water in the tank = 1000 L

Let y(t) denote the amount of salt in the tank at any time t.

Initially, the tank contains 60 kg of salt, therefore:

y(0)=60 kg

Rate In

A solution of concentration 0.03 kg of salt per liter enters a tank at the rate 9 L/min.

$R_{in}$ =(concentration of salt in inflow)(input rate of solution)

$=(0.03\frac{kg}{liter})( 9\frac{liter}{min})=0.27\frac{kg}{min}$

Rate Out

The solution is mixed and drains from the tank at the same rate.

Concentration, $C(t)=\dfrac{Amount}{Volume} =\dfrac{y(t)}{1000}$

$R_{out}$ =(concentration of salt in outflow)(output rate of solution)

$=\dfrac{y(t)}{1000}* 9\dfrac{liter}{min}=0.009y(t)\dfrac{kg}{min}$

Therefore, the differential equation for the amount of Salt in the Tank at any time t:

$\dfrac{dy}{dt}=R_{in}-R_{out}\\\\\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg$

8 0

4 years ago

WILL MARK BRAINLIEST PLEASE HELP ASAP !!! Roberto is paid $11 an hour at his new job He wishes to graph his total pay T, as a fu

Oliga [24]

To best show this information, the scale for the T-axis of his graph should go from 0 to at least 11, and the h-axis of his graph should go from 0 to at least 40.

Apologies for any incorrect answer, hope this helped.

7 0

4 years ago

Read 2 more answers

1/3(y - 2) -5/6 (y + 1) =3/4 (y - 3) - 2

Nataly [62]

Answer:

$y=\frac{11}{5}$

Step-by-step explanation:

Given expression

$\frac{1}{3}(y-2)-\frac{5}{6}(y+1)=\frac{3}{4}(y-3)-2$

To solve for $y$ for the given expression.

Solution:

We multiply each term with the least common multiple of the denominators of the fraction in order to remove fractions.

The multiples of the denominators are:

3 = 3,6,9,12,15

6 = 6,12

4 = 4,8,12

The least common multiple = 12.

Multiplying each term with 12.

$12.\frac{1}{3}(y-2)-12.\frac{5}{6}(y+1)=12.\frac{3}{4}(y-3)-2(12)$

$4(y-2)-10(y+1)=9(y-3)-24$

Using distribution.

$4y-8-10y-10=9y-27-24$

Simplifying.

$-6y-18=9y-51$

Adding $6y$ both sides.

$-6y+6y-18=9y+6y-51$

$-18=15y-51$

Adding 51 both sides.

$-18+51=15y-51+51$

$33=15y$

Dividing both sides by 15.

$\frac{33}{15}=\frac{15y}{15}$

$\frac{33}{15}=y$

Simplifying fractions.

$\frac{11}{5}=y$

∴ $y=\frac{11}{5}$ (Answer)

7 0

3 years ago