Answer:
?=25
Step-by-step explanation:
15/x=21/x+10
Cross Multiply
15X+150=21X
SUBTRACT 15 X ON BOTH SIDES.
150=6x
DIVIDE 6 IN BOTH SIDES.
x=25
Option C:
x = 6 units
Solution:
QR = 7 units, RS = 5 units, UT = 4 units and ST = x
<em>If two secants intersect outside a circle, the product of the secant segment and its external segment s equal to the product of the other secant segment and its external segment.</em>
⇒ SR × SQ = ST × SU
⇒ 5 × (5 + 7) = x × (x + 4)
⇒ 5 × 12 = x² + 4x
⇒ 60 = x² + 4x
Subtract 60 from both sides.
⇒ 0 = x² + 4x - 60
Switch the sides.
⇒ x² + 4x - 60 = 0
Factor this expression, we get
(x - 6)(x + 10) = 0
x - 6 = 0, x + 10 = 0
x = 6, x = -10
Length cannot be in negative measures.
x = 6 units
Option C is the correct answer.
Answer:
booger
Step-by-step explanation:
bc
<span>70=2(x+x-9)
</span><span>2x-9=35
x=22
</span><span>length 22, width 13</span>
Substitute y
6x + 5(2x – 14) = -6
use distributive property
6x + 10x – 70 = -6
add terms together
16x = 64
isolate x
16x/16 = 64/16
x = 4
to find value of y, use your x value in the second equation
y = 2(4) – 14
y = -6
Verify you are correct
6(4) + 5(-6) = -6