A rectangle has a base of 2 yd and a height of 5 ft. Find the area of the rectangle.

The population of a town can be modeled by P= 22,000 + 125t, where P represents the population and the t represents the number o

nlexa [21]

Given that the population can be modeled by P=22000+125t, to get the number of years after which the population will be 26000, we proceed as follows:
P=26000
substituting this in the model we get:
26000=22000+125t
solving for t we get:
t=4000/125
t=32
therefore t=32 years
This means it will take 32 years for the population to be 32 years. Thus the year in the year 2032

7 0

2 years ago

The cash drawer of the market contains $227. There are six more $5 bills than $10 bills. The number of $1 bills is two more than

k0ka [10]

Answer:

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

Step-by-step explanation:

There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

$x + 5*y + 10*z = 227$

We know that there are six more 5 dollar bills than 10 dollar bills and that the number of 1 dollar bills is two more than 24 times the number of 10 dollar bills, therefore:

$y = z + 6\\x = 2 + 24*z$

Applying these values on the first equation, we have:

$2 + 24*z + 5*(z + 6) + 10*z = 227\\2 + 24*z + 5*z + 30 + 10*z = 227\\39*z + 32 = 227\\39*z = 227 - 32\\39*z = 195\\z = \frac{195}{39}\\z = 5$

Applying z to the formulas of y and x, we have:

$y = 5 + 6 = 11\\x = 2 + 24*5 = 122$

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

4 0

2 years ago

Please check my answers for me. They are two questions, both I have answered, but I am not sure if I am fully correct

alekssr [168]

#1 is wrong and #2 is correct

3 0

2 years ago

Read 2 more answers

The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the

SVEN [57.7K]

Given,
The sum of three integers is 92

So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"

Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)

Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,

x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17

Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51

Now,
Substituting the value of "x" in equation (2),

z = 2 (17 ) - 10
z = 34 - 10
z = 24

So, the numbers are 17, 51 and 24

NEVER HATE MATH!!!

3 0

2 years ago

Use Fermat's Little Theorem to determine 7^542 mod 13.

m_a_m_a [10]

$a^{p-1} \equiv 1 \pmod p$ where $p$ is prime, $a\in\mathbb{Z}$ and $a$ is not divisible by $p$ .

$7^{13-1}\equiv 1 \pmod {13}\\7^{12}\equiv 1 \pmod {13}\\\\542=45\cdot12+2\\\\7^{45\cdot 12}\equiv 1 \pmod {13}\\7^{45\cdot 12+2}\equiv 7^2 \pmod {13}\\7^{542}\equiv 49 \pmod{13}$

4 0

2 years ago

Read 2 more answers