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3 years ago

Play help due tomorrow

Mathematics

1 answer:

IgorC [24]3 years ago

5 0

D. 42/8

You can get this by adding the blueberry and banana amounts together. Then multiply by 6.

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Quickly help please!!! Math!!!

Nezavi [6.7K]

Answer: f(x) = -5/2x+4

Step-by-step explanation: The function crosses over the y-axis at 4 and decreases at a rate of -5/2.

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3 years ago

Pls help !!!!!!!!!!!!!!!!!!!!!!!!!

jok3333 [9.3K]

Answer:

D. Rhombus.

Step-by-step explanation:

This will be a quadrilateral with 4 equal sides.

The oppsoite angles will be equal but they will not be 90 degrees as each triangle of the 3 dimensional figure is an equilateral triangle.

Therfore the cross section is a rhombus.

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2 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

erma4kov [3.2K]

Answer:

a) $n = 9604$

b) n = 381

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?

When we do not know the proportion, we use $\pi = 0.5$ , which is when we are going to need the largest sample size.

The sample size is n when M = 0.01.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.01\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.01}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.01})^{2}$

$n = 9604$

b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?

Now we have that $\pi = 0.99$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.96\sqrt{\frac{0.99*0.01}{n}}$

$0.01\sqrt{n} = 1.96*\sqrt{0.99*0.01}$

$\sqrt{n} = \frac{1.96*\sqrt{0.99*0.01}}{0.01}$

$(\sqrt{n})^{2} = (\frac{1.96*\sqrt{0.99*0.01}}{0.01})^{2}$

$n = 380.3$

Rouding up

n = 381

7 0

3 years ago

Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

My name is Ann [436]

Answer:

Part 1) $BE=266\frac{2}{3}\ ft$

Part 2) $PE=233\frac{1}{3}\ ft$

Step-by-step explanation:

Part 1)

Find the distance from B to E

To solve this problem I assume that CGRP is a parallelogram

Triangles CGB and PEB are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

$\frac{BG}{BE}=\frac{CB}{PB}$

substitute the values

$\frac{400}{BE}=\frac{300}{200}$

solve for BE

$BE=400(200)/300$

$BE=\frac{800}{3}\ ft$

Convert to mixed number

$BE=\frac{800}{3}\ ft=\frac{798}{3}+\frac{2}{3}=266\frac{2}{3}\ ft$

Part 2)

Find the distance from P to E

$\frac{CG}{PE}=\frac{CB}{PB}$

substitute the values

$\frac{350}{PE}=\frac{300}{200}$

solve for PE

$PE=350(200)/300$

$PE=\frac{700}{3}\ ft$

Convert to mixed number

$PE=\frac{700}{3}\ ft=\frac{699}{3}+\frac{1}{3}=233\frac{1}{3}\ ft$

5 0

3 years ago

Can some1 help? im a little confused:(

fgiga [73]

Answer:

Step-by-step explanation:

brainly.com/question/1701683

url to the help thingy

4 0

3 years ago