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Mariulka [41]
3 years ago
7

Solve for w. -9w+45=3 (w-1)

Mathematics
1 answer:
Kamila [148]3 years ago
4 0
W=4
I hope this helps! Any questions?
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June has a bakery. Her rent is $750 a month. Over a month, she sells 50 cakes, 120 cupcakes and 250 dozen cookies. This costs he
Charra [1.4K]

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$2,750

Step-by-step explanation:

Total spending = Rent + Cost

= $750 + $2000

= $2750

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Identify each of the following as rational or irrational
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104.42-rational
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8 0
2 years ago
How many ways can an employer send 3 employees to a job fair if she has 11 employees?
algol13

We have to find the number of ways an employer send 3 employees to a job fair if she has 11 employees.

This is the problem from combination.

The formula for combination is given by

^nC_r= \frac{n!}{r!(n-r)!}

Here, n= 11, r= 3

Therefore, total number of ways is given by

^{11}C_3= \frac{11!}{3!(11-3)!}\\
\\
=\frac{11!}{3!8!}\\
\\
=\frac{8!\times 9 \times 10 \times 11}{3!8!}\\
\\
=\frac{9 \times 10 \times 11}{6}\\
\\
=165

A is the correct option.


6 0
3 years ago
The U.S. Bureau of Labor Statistics reports that of persons who usually work full-time, the average number of hours worked per w
alukav5142 [94]

Answer:

The standard deviation of number of hours worked per week for these workers is 3.91.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem we have that:

The average number of hours worked per week is 43.4, so \mu = 43.4.

Suppose 12% of these workers work more than 48 hours. Based on this percentage, what is the standard deviation of number of hours worked per week for these workers.

This means that the Z score of X = 48 has a pvalue of 0.88. This is Z between 1.17 and 1.18. So we use Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{48 - 43.4}{\sigma}

1.175\sigma = 4.6

\sigma = \frac{4.6}{1.175}

\sigma = 3.91

The standard deviation of number of hours worked per week for these workers is 3.91.

6 0
3 years ago
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