Question

Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), xxx seconds after Amir threw it, is modeled by: h(x)=-(x-2)^2+16h(x)=−(x−2) 2 +16h, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 2, right parenthesis, start superscript, 2, end superscript, plus, 16 What is the height of the ball at the time it is thrown?

Answer 1

Answer:

At the moment it is thrown, the height of the ball is 12 meters

Step-by-step explanation:

If the function $h(x) = - (x-2) ^ 2 + 16$ models the height of the ball x seconds after it is thrown, then by this same function we can know the initial height of the ball at the initial moment.

If we represent the initial time instant as x = 0, then by doing h (0) we will get the initial height, just when the ball is thrown.

$h(0) = - (0-2) ^ 2 +16\\ h(0) = - (4) +16\\ h(0) = -4 +16$

h (0) = 12 meters.

At the moment it is thrown, the height of the ball is 12 meters

Answer 2

Answer:16 meters

Step-by-step explanation:

The height of the ball at the time it is thrown is given by

h

(

0

)

h(0)h, left parenthesis, 0, right parenthesis.

h

(

0

)

=

−

2

(

0

)

+

4

(

0

)

+

1

6

=

0

+

0

+

1

6

=

1

6

h(0)

​

=−2(0)

2

+4(0)+16

=0+0+16

=16

​