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ExtremeBDS [4]
3 years ago
5

Is the following relation a function?

Mathematics
2 answers:
rjkz [21]3 years ago
3 0
Because for each x-value in the domain of this relationship, except for 0, there is more than one y-value, this is NOT a function.  
garri49 [273]3 years ago
3 0
Hello!

This relation is not a function. Each input (domain or x value) must have only one output (range or y value). If you look at some of the x values, there are two points where  the relation will intersect the x value. 

For example, on this question (points aren't exact, this is just from perspective) there are points (1,1) and (1,-1). As you can see, this one has two outputs, so it is not a function.

A good way to test to see if a relation is a function is the "vertical line test". You draw (or imagine just to be a quick) a vertical line down towards the graphed relation. This vertical line can only intersect with the graphed relation ONCE. If it intersects with two parts of the relation, it is not a function.

In this scenario, if you drew a vertical line down at x=5, it would intersect with the relation at about 2 and negative 2. Since it intersected twice with the graphed relation, it is not a function.

I hope this helps!
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Casey was twice as old as his sister 3 years ago. Now he is 5 years older than his sister. How old is Casey?
Margarita [4]
Let x is Casey's sister age.
<span>3 years ago: 
</span><span>Casey was twice as old as his sister: 2a - 3
Now: 
</span><span>he is 5 years older than his sister: a + 5

2a - 3 = a + 5
subtract a to both sides
2a - 3 -a = a + 5 - a
simplify
a - 3 = 5
add 3 to both sides
a - 3 + 3 = 5 + 3
simplify
a = 8

His sister age is 8 years old now.
</span>Now: 
he is 5 years older than his sister: a + 5 = 8 + 5 = 13
<span>
proof: 
so 3 years ago,
his sister age: 8 - 3 = 5
Casey age 3 years ago:
13 - 3 = 10 (</span>C<span>asey was twice as old as his sister 3 years ago</span>)
<span>
Answer:
Casey is 13 years old now.


</span>
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:D

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